k^2-1.5k-10=0

Solution for k^2-1.5k-10=0 equation:

k^2-1.5k-10=0

a = 1; b = -1.5; c = -10;
Δ = b2-4ac
Δ = -1.52-4·1·(-10)
Δ = 42.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.5)-\sqrt{42.25}}{2*1}=\frac{1.5-\sqrt{42.25}}{2}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.5)+\sqrt{42.25}}{2*1}=\frac{1.5+\sqrt{42.25}}{2}
$